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One gram mole of nitrogen at 27^(@)C and 1 atm pressure is contained in a vessel and the molecules are moving with their speed. The number of collisions per second which the molecules make with an area of 1m^(2) on the vessel's wall is |
Answer» <html><body><p>`2xx10^(27)` <br/>`2xx10^(20)`<br/>`2xx10^(10)`<br/>`2xx10^(<a href="https://interviewquestions.tuteehub.com/tag/24-295400" style="font-weight:bold;" target="_blank" title="Click to know more about 24">24</a>)`</p>Solution :Number of collisions can be calculated as `n(2mv_(rms))=PA` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> n=[(PA)/(2mv_(rms))],"where "v_(rms)=[(3RT)/(M)]^(1//2)` <br/> `v_(rms)=sqrt((3xx8.3xx300)/(28xx10^(-3)))=516.8m//s` <br/> `m=1g"mole"=(<a href="https://interviewquestions.tuteehub.com/tag/28-299271" style="font-weight:bold;" target="_blank" title="Click to know more about 28">28</a>)/(6.02xx10^(26))` <br/> On solving, we get `n=2xx10^(27)`</body></html> | |