1.

One gram mole of nitrogen at 27^(@)C and 1 atm pressure is contained in a vessel and the molecules are moving with their speed. The number of collisions per second which the molecules make with an area of 1m^(2) on the vessel's wall is

Answer»

`2xx10^(27)`
`2xx10^(20)`
`2xx10^(10)`
`2xx10^(24)`

Solution :Number of collisions can be calculated as `n(2mv_(rms))=PA`
`THEREFORE n=[(PA)/(2mv_(rms))],"where "v_(rms)=[(3RT)/(M)]^(1//2)`
`v_(rms)=sqrt((3xx8.3xx300)/(28xx10^(-3)))=516.8m//s`
`m=1g"mole"=(28)/(6.02xx10^(26))`
On solving, we get `n=2xx10^(27)`


Discussion

No Comment Found

Related InterviewSolutions