One is asked to say a two digit number. what is the probability.a. Bot

1.	One is asked to say a two digit number. what is the probability.a. Both digits being different b. The first digit being largerc. The first digit being smaller.
Answer» There are 90 TWO DIGIT numbers(99–9). Out of this there are 6 numbers divisible by 15(15, 30, 45, 60, 75, 90), which are also divisible by 5. Therefore, the favorable CASES are 30–6=24. Hence, the REQUIRED probability is 24/90 = 4/15.

One is asked to say a two digit number. what is the probability.a. Both digits being different b. The first digit being largerc. The first digit being smaller.

Answer»

There are 90 TWO DIGIT numbers(99–9). Out of this there are 6 numbers divisible by 15(15, 30, 45, 60, 75, 90), which are also divisible by 5. Therefore, the favorable CASES are 30–6=24. Hence, the REQUIRED probability is 24/90 = 4/15.

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One is asked to say a two digit number. what is the probability.a. Both digits being different b. The first digit being largerc. The first digit being smaller. ​

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One is asked to say a two digit number. what is the probability.a. Both digits being different b. The first digit being largerc. The first digit being smaller.