1.

One litre each of a Buffer solution is taken in two beakers connected through a salt bridge. Platinum electrode is immersed in each beaker and electrysis is carried out for 10,000 sec. using a current of 9.65 Ampere. The Buffer contain (1)/(3) mole each of Na_(2)HPO_(4) and NaH_(2)PO_(4) Initially. using the given data answer the following. Given: ltbr. pK_(a) (H_(3)PO_(4)) = 4, pK_(a) (H_(2)PO_(4)^(-)) = 7 , pK_(a) (HPO_(4)^(2-)) = 10 log 2 = 0.3, log3 = 0.48 2.303 (RT)/(F) = 0.06 at 298K After electrolysis if H_(2) gas is bubbled at 1 bar pressure on each platinum electrode, what is the EMF of resulting Galvenic cell.

Answer»

`1.09V`
`0.29V`
`0.59V`
`0.39V`

SOLUTION :`EMF = E_("cathode") - E_("Anode")`
`E_(H^(+)//H_(2)) = E_(H^(+)//H_(2))^(@) -(0.0591)/(2)log.(1)/([H^(+)]^(2))`
`E_(H^(+)//H_(2)) =- 0.059 PH`
`EMF =- 0.0591 pH_("cathode") -(-0.0591 pH_("anode"))`
`= (pH_("anode") -pH_("cathode")) 0.06`
`= (11.91 -2.09) 0.06`
`= 0.59`


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