Saved Bookmarks
| 1. |
One litre of a mixture of O_(2) and O_(3) at NTP was allowed to react with an excess of acidified solution of KI. The iodine liberated required 40 mL of M/10 sodium thiosulphate solution for titration. The weight percent of ozone in the mixture is |
|
Answer» 0.0557 `{:(2 KI+H_(2)SO_(4)+(O)rarr K_(2)SO_(4)+H_(2)O+I_(2)),(2 Na_(2)SO_(3)+I_(2) rarr Na_(2)S_(4)O_(6)+2" NAI"),(bar(2 Na_(2)S_(2)O_(3)+2 KI+O_(3)+H_(2)SO_(4) rarr O_(2)+K_(2)SO_(4)+H_(2)O+Na_(2)S_(4)O_(6)+2" NaI")):}` 2 moles of `Na_(2)S_(2)O_(3)` react with one MOLE of `O_(3)` No. of moles `Na_(2)S_(2)O_(3)` in 40 ml of `M/10 Na_(2)S_(2)O_(3)` `=1/10xx1/1000xx40=4xx10^(-3)` mole `:. O_(3)` reacted (present) `=2xx10^(-3)` mole VOLUME of `O_(3)=2xx10^(-3)xx22.4 L=0.0448 L` `:.` Volume of `O_(2)=1-0.0448=0.9552 L` Weight of `O_(3)=2xx10^(-3)xx48=0.096 g` Weight of `O_(2) =(0.9552)/22.4xx32=1.3646 g` `:.` Weight of mixture `=0.096+1.3646` `=1.4606 g` `:.` % of `O_(3)` by weight `=0.096/1.4606xx100=6.573%`. |
|