1.

One litre of a sample of hard water contains 4.44 mg CaCl_2 and 1.9 mg of MgCl_2.What is the total hardness in terms of ppm of CaCO_3 ?

Answer»


Solution :4.44 mg `CaCl_2` is equivalent to 4 mg `CaCO_3`
1.9 mg `MgCl_2` is equivalent to 2 mg `CaCO_3`
TOTAL wt. of `CaCO_3=6` mg
HARDNESS in PPM =`(6xx10^(-3))/10^3 xx10^6=6` ppm


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