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One litre of oxygen at NTP is allowed to reasonanace with three times of carbon monoxide at NTP. Calculate the volume of each gas found after the reaction. |
Answer» The reaction equation is `underset(2"vol")(2CO)+underset(1"vol")(O_(2)) to underset(2"vol")(2CO_(2))` `"1 vol of" O_(2) "reacts with 2 vol. of CO"` or `"1 litre of" O_(2) "reacts with 2 vol. of CO"` `"Thus 1 litre of CO remains unchanged"` `"1 vol. of" O_(2) "produces" CO_(2)=2"vol"` `or "1 litre of" O_(2) "will produce" CO_(2)="2litre"` Thus, gaseous mixture after the reaction consists. Volume of CO=1litre Volume of `CO_(2)`=2 litre |
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