1.

one man has 4 sons. the total of all the ages of the 4 is 45. if the first son age is divided by 2,from second son age 2is subtracted, 2 is added to third son age and fourth son age is multiplied with 2 you will get the same number. what is the age of each one ​

Answer»

Step-by-step explanation:

Let the age of all the sons be x

By condition,

x/2 + x-2 + x+2 + x×2 = 45

=> x + x-2 + x+2 + x = 45

=> 4X = 45 => x = 45/4 = 11.25

Age of first son = x/2 = 11.25/2 = 5.625

Age of second son = x-2 = 11.25 - 2 = 9.25

Age of third son = x+2 = 11.25 + 2 = 13.25

Age of fourth son = x×2 = 11.25 × 2 = 22.5

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