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One mole ideal monatomic gas is taken at temperature of 300 K. If volume is doubled keeping its pressure constant. The change in the internal energy is |
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Answer» 450 R `therefore (V_(i))/(T_(i))=(V_(F))/(T_(f))` or `T_(f)=(V_(f))/(V_(i))T_(i)=2T_(i)=2xx300=600K` `therefore DeltaU=(f)/(2)nRDeltaT` (f = degrees of freedom) `=(3)/(2)xx1xxRxx(600-300)=450R` |
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