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One mole o `N_(2)O_(4)` gasat 300 is keip in a closed ctainer at 1 atm. It is heatedto 600 K when `20%` by mass of `N_(2)O_(4)` decomposes to `NO_(2(g)).` The resultant pressure in the container would beA. `1.2` atmB. `2.4` atmC. `2.0` atmD. `1.0` atm |
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Answer» Correct Answer - C `{:("Initial",1,0),("no. of moles",,),("No. of moles",(1-0.2),0.4),("at equlibrium",,):}` Total number of moles at equlibrium `=1.2` Initially, `P_(1)V=n_(1)RTor 1xxV=1xxRT_(1)or V=RT_(1)` At equlibrium, `P_(2)V=n_(2)RT_(2)` `or,P_(2)=(1.2)/(V)RT_(2)=(1.2)/(RT_(1))RT_(2)=(1.2xx600)/(300)=2.4atm.` |
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