1.

One mole o N_(2)O_(4) gasat 300is keip in a closed ctainer at 1 atm. It is heatedto 600 K when 20% by mass of N_(2)O_(4) decomposes to NO_(2(g)). The resultant pressure in the container would be

Answer»

`1.2` ATM
`2.4` atm
`2.0` atm
`1.0` atm

Solution :`{:("INITIAL",1,0),("no. of moles",,),("No. of moles",(1-0.2),0.4),("at equlibrium",,):}`
Total number of moles at equlibrium `=1.2`
INITIALLY, `P_(1)V=n_(1)RTor 1xxV=1xxRT_(1)or V=RT_(1)`
At equlibrium, `P_(2)V=n_(2)RT_(2)`
`or,P_(2)=(1.2)/(V)RT_(2)=(1.2)/(RT_(1))RT_(2)=(1.2xx600)/(300)=2.4atm.`


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