1.

One mole of a compound AB reacts with one mole of a compound CD accoeding to the equation AB+CDhArrAD+CB. When equilibrium had been estblished it was found that 3/4 mole each of rectant AB and CD had been converted to AD and CB. There is no change in volume. The equlibrium constant for the reaction is

Answer»

`9/16`
`1/9`
`16/9`
9

Solution :`AB+CD hArrAB+CD`
`{:("MOLE at t=0",1,1,0,0),("Mole at equlibrium",(1-(3)/(4)),(1-(3)/(4)),((3)/(4)),((3)/(4))),(,0.25,0.25,0.75,0.75):}`
`K_(C)=(0.75xx0.75)/(0.25xx0.25)=(0.5625)/(0.0625)=9`


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