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One mole of a gas expands with temperature T such thaht its volume, V=`KT^(2)`, where K is a constant. If the temperature of the gas changes by `60^(@)C` then the work done by the gas is

Answer» Correct Answer - `1000J`
`W = int PdV , V = kT^(2)` (given)
`PdV = 2nRdT :. W = int PdV = 2nR int dT`
`W = 2nR DeltaT = 2 xx 1 xx R xx 60`
`W = 120 R= 120 xx 25//3 = 1000J`


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