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One mole of a gas expands with temperature T such thaht its volume, V=`KT^(2)`, where K is a constant. If the temperature of the gas changes by `60^(@)C` then the work done by the gas is |
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Answer» Correct Answer - `1000J` `W = int PdV , V = kT^(2)` (given) `PdV = 2nRdT :. W = int PdV = 2nR int dT` `W = 2nR DeltaT = 2 xx 1 xx R xx 60` `W = 120 R= 120 xx 25//3 = 1000J` |
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