InterviewSolution
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InterviewSolution
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One mole of a monoatomic gas behving ideally is used as working substance in an engine working in the cycle as shown in the figure . The process AB, BC, CD and DA are respectively reversible isobaric, adiabatic isochoric and isothermal . The ratio of maximum to volume and temperature during the cycle is `8sqrt(2)` and 4 respectively. If the maximum T is 800 K and `gamma =5//3`. Calculate `DeltaE` (in kJ) for the process BC. Given `R= 8.3 J//K-mol`. |
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Answer» Correct Answer - `DeltaE = 2.49 KJ` Max. volume at `V_(A)` Min. volume at `V_(C)` & `V_(D)` `(V_(A))/(V_(C))= 8sqrt(2)` `V_(A)= 8sqrt(2) V_(C)` nin. Temp .at B max. temp at D or A `(T_(D))/(T_(B))= 4 or (T_(A))/(T_(B))= 4` `therefore T_(B) = 200 K` During isobaric process Ab `(V_(A))/(V_(B))= (T_(A))/(T_(B)) rArr V_(B) (T_(B))/(T_(A))= (8sqrt(2))/(4) V_(C) = 2 sqrt(2) V_(C)` During adiabatic proess BC `T_(C)= T_(B) ((V_(B))/(V_(C)))^(r-1)= 200 (2sqrt(2))^((5)/(3)-1)=400 K` `= 400 K` `DeltaE= (3)/(2)R[400-200]` `= 2494 .2 J = 2.494 kJ` |
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