1.

One mole of a monoatomic gas undergoes a linear process A rarr B in P - v diagram. The volume of the gas when the process turns from an endothermic to an exothermic one is

Answer»

`(5)/(8)v_(0)`
`(v_(0))/(2)`
`(8v_(0))/(15)`
`(3v_(0))/(5)`

Solution :the point whereadiabatic curve touch the line AB the nature of process will CHANGE from endo thermic to exothermic.

`-(P_(0))/(v_(0))=-gamma(P)/(V)`
`-m=-(gamma(-mv+P_(0)))/(V) m =+(P_(0))/(V_(0))`
`mv(1+gamma)=gammaP_(0) "" V=(gammaP_(0))/(m(1+gamma))=(5)/(8)V_(0)`


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