1.

One mole of a perfect gas expands isothermally to ten times of its original volume. The change in entropy is

Answer»

0.1 R
2.303 R
10.0 R
100.0 R

Solution :We KNOW that, `DeltaS=2.303" NR log "(V_(2))/(V_(1))`
`therefore DeltaS=2.303R" log"(10)/(1)`
`DeltaS=2.303R""(because log10=1)`


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