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One mole of a real gas is subjected to a process from (2 bar , 30 lit ., 300k) to (2 bar , 40 , lit ., 500K) Given :`C_(v)=25 J//"mole"/K` `C_(p)=40 J//"mole"/K` Calculate `DeltaU`.A. 5000 JB. 6000 JC. 8000 JD. 10000 J |
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Answer» Correct Answer - B `DeltaU=q+"w"` `=(40xx200)+(-2xx10xx100)` `= 6000 J ` |
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