1.

One mole of a symmetrical alkene on hydrolyses gives two moles of an aldehyde having a molecular mas of 44 u. The alkene is

Answer»

2-butene
ethene
propene
1-butene.

Solution :The aldehyde with molecular MASS will 44u is `CH_(3)CHO` (ACETALDEHYDE) `therefore` symmetrical ALKENE is 2-butane
`underset("2-butene")(CH_(3)CH=CHCH_(3))OVERSET((i)O_(3))underset((ii)Zn//H_(2)O)rarrundersetunderset("Mol. mass=44")("Acetaldehyde")(2CH_(3)CHO)`


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