One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in (figure). The change in internal energy of the gas during the transition is `(gamma=3//5)` A. `-20 KJ`B. `20 KJ`C. `-12 KJ`D. `20 KJ`

One mole of an ideal diatomic gas undergoes a transition from A to B a

1.	One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in (figure). The change in internal energy of the gas during the transition is `(gamma=3//5)` A. `-20 KJ`B. `20 KJ`C. `-12 KJ`D. `20 KJ`
Answer» Correct Answer - A Here, `P_(1)= 5Kpa, P_(2)= 2Kpa` `V_(1)= 4m^(3), V_(2)= 6m^(3), r= 3//5` As change is internal energy `DeltaU= n C_(v)DeltaT= (PV)/(nR)` `DetlaT=T_(2)-T_(1)=(P_(2)V_(2)-P_(1)V_(1))/(nR), C_(v)= R/(gamma-1)` `DeltaU=(nR)/(gamma-1)((P_(2)V_(2)-P_(1)V_(1))/(nR))=(P_(2)V_(2)-P_(1)V_(1))/(gamma-1)` `=(5xx4-2xx6)/(3/5-1)=(200-12)/(-2/5)= -8/(2/5)=-20KJ`

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One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in (figure). The change in internal energy of the gas during the transition is `(gamma=3//5)` A. `-20 KJ`B. `20 KJ`C. `-12 KJ`D. `20 KJ`

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