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One mole of an ideal gas at an initial temperature of TK does 6 R joule of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 5/3, the final temperature of the gas will be: |
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Answer» `(T+4)K` `6R =(R )/((5)/(3)-1)(T-T_(2))` `T_(2)=(T-4)K`. `THEREFORE` Correct choice is (c ). |
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