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One mole of an ideal gas at temperature `T_` expands slowly according to the law `p/V=` constant. Its final temperature is `T_2`. The work done by the gas isA. `R(T_(2) - T_(1))`B. `2R(T_(2) - T_(1))`C. `R/2(T_(2) - T_(1))`D. `2R/3(T_(2) - T_(1))` |
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Answer» Correct Answer - C `PV^(-1)=C` Comparing `PV^(N) = C` `N+-1` `W=(nR(T_1-T_2))/(N-1) = (1xxR(T_1-T_2))/(-2)` `W = (R(T_2-T_1))/(2)` . |
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