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One mole of an ideal gas (`C_(V) = 20 JK^(-1) mol^(-1))` initially at STP is heated at constant volume to twice the initial temeprature. For the process W and q will beA. W = 0, q = 5.46 kJB. W = 0,q=0C. W = -5.46kJ, q = 5.46 kJD. W=5.46kJ, q = 5.46 kJ |
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Answer» Correct Answer - A `W = P Delta V = P xx 0 = 0` `Q = C_(V) (Delta T) = 20 xx 273 = 5460 J = 5.46 kJ` |
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