One mole of an ideal gas is supplied 2KJ of heat. If the temperature o

1.	One mole of an ideal gas is supplied 2KJ of heat. If the temperature of the gas rises from 0°C to 200°C, calculate work done by the gas and change in its internal energy if 1. The process Is isobaric 2. The process is isochoric.
Answer» number of moles, n = 1 Initial temperature, T_i = (0 + 273) = 273 K Final temperature, T_f = (200 + 273) = 473 K Net heat supplied, H = 2000 J 1. Isobaric process : work done, W = P - ∆ V or W = n R∆T ∴ W= 1 × 8.314 × (473-273) ∴ W= 1662.8J = 1.66KJ ∴ Change in internal energy, ∆U = H - W= 2000 - 1662.8 = 337.2J 2. isochoric Process: Work done in an isochoric process , W =0. Therefore change in internal energy ∆U = H = 2 kJ.

One mole of an ideal gas is supplied 2KJ of heat. If the temperature of the gas rises from 0°C to 200°C, calculate work done by the gas and change in its internal energy if 1. The process Is isobaric 2. The process is isochoric.

Answer»

number of moles, n = 1

Initial temperature, T_i = (0 + 273)

= 273 K

Final temperature, T_f = (200 + 273)

= 473 K

Net heat supplied, H = 2000 J

1. Isobaric process :

work done, W = P - ∆ V

or W = n R∆T

∴ W= 1 × 8.314 × (473-273)

∴ W= 1662.8J = 1.66KJ

∴ Change in internal energy,

∆U = H - W= 2000 - 1662.8

= 337.2J

2. isochoric Process:

Work done in an isochoric process , W =0. Therefore change in internal energy

∆U = H = 2 kJ.

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One mole of an ideal gas is supplied 2KJ of heat. If the temperature of the gas rises from 0°C to 200°C, calculate work done by the gas and change in its internal energy if 1. The process Is isobaric 2. The process is isochoric.

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