One mole of an ideal gas undergoes a process in which `T = T_(0) + aV^(3)`, where `T_(0)` and `a` are positive constants and V is molar volume. The volume for which pressure with be minimum isA. `((T_(0))/(2a))^(1//3)`B. `((T_(0))/(3a))^(1//3)`C. `(a)/(2T_(0))^(2//3)`D. `(a)/(3T_(0))^(2//3)`

One mole of an ideal gas undergoes a process in which `T = T_(0) + aV^

1.	One mole of an ideal gas undergoes a process in which `T = T_(0) + aV^(3)`, where `T_(0)` and `a` are positive constants and V is molar volume. The volume for which pressure with be minimum isA. `((T_(0))/(2a))^(1//3)`B. `((T_(0))/(3a))^(1//3)`C. `(a)/(2T_(0))^(2//3)`D. `(a)/(3T_(0))^(2//3)`
Answer» Correct Answer - A `T=T_(0)+aV^(3)implies (PV)/(nR) = T_(0)+aV^(3)` `P=nR[(T_0)/(V)+aV^(2)]` For minimum `P, (dP)/(dV)=0` `implies (-T_(0))/(V^2) + a2V=0implies V=((T_0)/(2a))^(1//3`.

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One mole of an ideal gas undergoes a process in which `T = T_(0) + aV^(3)`, where `T_(0)` and `a` are positive constants and V is molar volume. The volume for which pressure with be minimum isA. `((T_(0))/(2a))^(1//3)`B. `((T_(0))/(3a))^(1//3)`C. `(a)/(2T_(0))^(2//3)`D. `(a)/(3T_(0))^(2//3)`

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