One mole of an ideal gas undergoes a process P = P0 (1 + (2V0V)2]−1 – InterviewSolution

1.	One mole of an ideal gas undergoes a process P = P0 (1 + (2V0V)2]−1,where P0, V0 are constants. Change in temperature of the gas when volume is changed from V=V0to V=2V0 is nPoV0R. Then n is
Answer» One mole of an ideal gas undergoes a process $P = P_{0} {(1 + {(\frac{2 V_{0}}{V})}^{2}]}^{- 1},$ where $P_{0}, V_{0}$ are constants. Change in temperature of the gas when volume is changed from $V = V_{0}$ to $V = 2 V_{0}$ is $\frac{n P_{o} V_{0}}{R}$ . Then $n$ is

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