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| 1. |
One mole of an ideal gas undergoes cyclic change as shown. The work done in the process is (taking 1 atmosphere =10^(6)" dyne/"cm^(2)): |
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Answer» 100J `=DC xxBC =3" litre"xx3` atmosphere `=3xx10^(-3) m^(3)xx3xx10^(5)" N/m"^(2)`. `=9XX10^(2)=900 J`. Thus, correct CHOICE is (d). |
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