1.

One mole of an ideal gas undergoes cyclic change as shown. The work done in the process is (taking 1 atmosphere =10^(6)" dyne/"cm^(2)):

Answer»

100J
300J
700J
900J

Solution :Work DONE in complete eycle =AREA under the rectangle ABCD

`=DC xxBC =3" litre"xx3` atmosphere
`=3xx10^(-3) m^(3)xx3xx10^(5)" N/m"^(2)`.
`=9XX10^(2)=900 J`.
Thus, correct CHOICE is (d).


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