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One mole of an ideal monoatomic gas is mixed with 1 mole of an ideal diatomic gas The molar specific heat of the mixture at constant volume is .A. `3cal`B. `4cal`C. `8cal`D. `9cal`

Answer» `C_(v) = (3)/(2)R` (for monoatomic) and `(5)/(2)R` (for diatomic) Thus for mixture
`C_(v)=[[(3)/(2)R+(5)/(2)R]]/(2) =2R =4cal` .


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