1.

One mole of an non linear triatomic ideal gas is compressed adiabatically at 300 K from 1 atom to 16 atm. Calculate Work done under the following conditions. (i) Expansion is carried out reversibly. (ii) Expansion is carried out irreversibly.

Answer»

SOLUTION :q = 0 Adiabatic PROCESS
(i) `W_("rev")=DeltaU=C_(V)(T_(2)-T_(1))`
`P^(1-gamma)T^(gamma)=K`
`T_(2)=300(1/16)^((1-4//3)/(4//3))=600K`
w = 3R (600 - 300) = 900 R
(ii) `W_("irr")=-P_("EXT")(V_(2)-V_(1))=-P_("ext")((nRT_(2))/P_(2)-(nRT_(1))/P_(1))`
`-P_("ext")((nRT_(2))/P_(2)-(nRT_(1))/P_(1))=C_(v)(T_(2)-T_(1))`
`-16((RT_(2))/16-(RT_(1))/1)=3R(T_(2)-T_(1))`
`-(T_(2)-16T_(1))=3R(T_(2)-T_(1))`
`-T_(2)+16T_(1)=3T_(2)-3T_(1)`
`4T_(2)=19T_(1)`
`T_(2)=19/4xx300=1425K`
`w=DeltaU=3R(1425-300)=3375R`


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