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One mole of an organic compound (A) having M.F. C_(2)H_(6)O reacts with MeMgI to liberate one mole of methane. (A) reacts with CH_(3)COCl to yield a sweet smelling liquid (B). Identify (A) and (B). |
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Answer» Solution :(i) Since compound (A) with M.F. `C_(2)H_(6)O` reacts with MeMgI to give one mole of `CH_(4)`, the compound (A) must be ETHYL alcohol. `MeMgI-=CH_(3)MgI` `underset("Ethyl alcohol")(CH_(3)CH_(2)OH)+CH_(3)MgI to CH_(3)+Mg(OCH_(2)CH_(3))I` (II) Compound A, i.e., ethyl alcohol reacts with acetyl chloride `(CH_(3)COCl)` to form sweet smelling compound (B). therefore, compound (B) must be ethyl acetate. `underset("Acetyl chloride")(CH_(3)COCl)+underset("Ethyl alcohol")(HOCH_(2)CH_(3)) to underset("Ethyl acetate (B)")(CH_(3)CO-OCH_(2)CH_(3)+HCl)` |
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