1.

One mole of any substance contains 6.022xx10^(23) atoms/molecules. Number of molecules of H_(2)SO_(4) present in 100 mL of 0.02 M H_(2)SO_(4) solutions is …………….. .

Answer»

`12.044xx10^(20)" molecules"`
`6.022xx10^(23)" molecules"`
`1xx10^(23)" molecules"`
`12.044xx10^(23)" molecules."`

SOLUTION :`"1000 mL of 1 M "H_(2)SO_(4)" contain = 1 mole of "H_(2)SO_(4)`
`"100 mL of 0.02 M "H_(2)SO_(4)" contain "H_(2)SO_(4)=(1)/(1000)xx100xx0.02" mole"=0.002" mole"=2xx10^(-3)" mole"`
`=2xx10^(-3)xx(6.022xx10^(23))" molecules"=12.044xx10^(20)" molecules."`


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