1.

One mole of ethanol is treated with one mole of ethanoic acid at `25^(@)C`. Half of the acid changes into ester at equilibrium. The equilibrium constant for the reaction will beA. `1`B. `2`C. `3`D. `4`

Answer» Correct Answer - A
`{:(,C_(2)H_(5)OH,+,CH_(3)COOH,hArr,CH_(3)COOC_(2)H_(5),+,H_(2)O),("Initial",1,,1,,0,,0),("At equ.",1-1/2,,1-1/2,,1/2,,1/2):}`
`K=([CH_(3)COOC_(2)H_(5)][H_(2)O])/([C_(2)H_(5)OH][CH_(3)COOH])=(1/2xx1/2)/(1/2xx1/2)=1`


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