One mole of ethyl alcohol was treated with one mole of acetic acid at `25^(@)C.` Two-third of the alcohol change into easter at equlibrium. The equlibrium constant for the reaction will beA. 1B. 2C. 3D. 4

One mole of ethyl alcohol was treated with one mole of acetic acid at

1.	One mole of ethyl alcohol was treated with one mole of acetic acid at `25^(@)C.` Two-third of the alcohol change into easter at equlibrium. The equlibrium constant for the reaction will beA. 1B. 2C. 3D. 4
Answer» Correct Answer - D `C_(2)H_(2)OH+COOHtoCH_(3)COOC_(2)H_(5)+H_(2)O` `{:("Initial conc.","1 mol","1 mol","0 mole","0 mole"),("At equlibrium", 1-2/3=1/3 "mol",1/3"mol",2/3"mol",2/3"mol"):}` `K_(C)=((2)/(3)xx(2)/(3))/(1/2xx1/3)=4`

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One mole of ethyl alcohol was treated with one mole of acetic acid at `25^(@)C.` Two-third of the alcohol change into easter at equlibrium. The equlibrium constant for the reaction will beA. 1B. 2C. 3D. 4

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