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One mole of gas is taken from state `A` to state `B` as shown in figure. Work done by the gas is `alpha xx 10^(beta)J`. Find the value of `alpha + beta`. (Given: ` T_(1) = 320 K , R = (25)/(3)`) |
Answer» Correct Answer - 7 Work done = `(1)/(2) [P_(0) + 2P_(0)][2V_(0)-V_(0)] = (3)/(2)P_(0)V_(0)` and `P_(0)V_(0) = R xx 320` So work done `(3)/(2)xx R xx 320 = (3)/(2) xx (25)/(3) xx320 = 4000J = 4 xx 10^(3)J implies alpha + beta = 4+3 = 7` |
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