1.

One mole of ice is coverted into water at 273 K. The entropies of H_(2)O(s) and H_(2)O(l) are 38.20 and 60.01 J mol^(-1) K^(-1) respectively. The enthaply change for the conversion is

Answer»

`59.54 J mol^(-1)`
`5954 J mol^(-1)`
`595.4 J mol^(-1)`
`320.6 J mol^(-1)`

SOLUTION :`H_(2)O(s) hArr H_(2)O(L)`
`DELTA S = S[H_(2)O(l)] - [H_(2)O(s)]`
`60.01 - 38.20`
`= 21.81 J mol^(-1)`
`Delta H = T Delta S = 21.81 xx 273`
`= 5954 J mol^(-1)`


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