One mole of ideal monoatmic gas is carried throught the reversible cyclic process as shown in figure. Calculate net heat absorbed by the gas in the path BC A. `(1)/(2)P^(@)V^(@)`B. `(7)/(2)P^(@)V^(@)`C. `2P^(@)V^(@)`D. `(5)/(2)P^(@)V^(@)`

One mole of ideal monoatmic gas is carried throught the reversible cyc

1.	One mole of ideal monoatmic gas is carried throught the reversible cyclic process as shown in figure. Calculate net heat absorbed by the gas in the path BC A. `(1)/(2)P^(@)V^(@)`B. `(7)/(2)P^(@)V^(@)`C. `2P^(@)V^(@)`D. `(5)/(2)P^(@)V^(@)`
Answer» Correct Answer - A `DeltaE=q+w` `W_(BC) =(1)/(2) (2V^(@) -V^(@))(P^(@)-3P^(@))(0-P^(@))=-2P^(@)V^(@)` `DeltaE=nC_(v)DeltaT=1xx(3)/(2)R((P^(@)2V^(@))/(R)-(3P^(@)V^(@))/(R)) =-(3)/(2) P^(@)V^(@)` `q_("BC")=DeltaE-W=-(3)/(2) P^(@)V^(@)+2P^(@)V^(@)=(1)/(2)P^(@)V^(@)`

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One mole of ideal monoatmic gas is carried throught the reversible cyclic process as shown in figure. Calculate net heat absorbed by the gas in the path BC A. `(1)/(2)P^(@)V^(@)`B. `(7)/(2)P^(@)V^(@)`C. `2P^(@)V^(@)`D. `(5)/(2)P^(@)V^(@)`

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