One mole of monoatomic gas is mixed with three moles of diatomic gas. What is molecular specific heat of the mixture at constant volume ? R = 8.31 J/mole/K:

One mole of monoatomic gas is mixed with three moles of diatomic gas.

1.	One mole of monoatomic gas is mixed with three moles of diatomic gas. What is molecular specific heat of the mixture at constant volume ? R = 8.31 J/mole/K:
Answer» 18.7 J/mole/K 1.87 J/mole/K 9.35 J/mole/K 4.67 J/mole/K. Solution :For monoatomic GAS `C_(v)=3//2 R` For diatomic gas `C_(v).=5//2 R` `(C_(v))_("MIX")=(nC_(v)+n.C.v)/((n+n.))` `=(1xx(3)/(2)R +3xx(5)/(2) R)/(1+3)` `=(9)/(4) R=(9)/(4) xx8.31` `=18.7` J/mole/K. `therefore` Correct choice is (a).

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One mole of monoatomic gas is mixed with three moles of diatomic gas. What is molecular specific heat of the mixture at constant volume ? R = 8.31 J/mole/K:

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