1.

One mole of oxygen at 273 K and one mole of sulphur dioxide at 546 K are taken in two separate containers, then

Answer»

kinetic energy of both are equal
kinetic energy of `O_(2) lt` kinetic energy of `SO_(2)`
kinetic energy of `O_(2) gt` kinetic energy of `SO_(2)`
none of these.

Solution :For OXYGEN, n = 1 mole, T = 273 K
Molecular mass of `O_(2) = 2 XX 16 = 32`
For SULPHUR DIOXIDE, n = 1 mole.
T = 546 K = 2(273)K
Molecular mass of `SO_(2) = 32 + 2(16) = 64`
Kinetic energy = (3/2)RT
`(K.E_(I))/(K.E_(II)) = ((3)/(2) xx Rxx T)/((3)/(2) xx R xx 2T) = 1/2`
`therefore` Kinetic energy of `SO_(2) gt` Kinetic energy of `O_(2)`.


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