1.

One mole of SO_(3) was placed in a litre reacton vesel at a certain temperaturee. The following equilibrium was established 2SO_(3)hArrSO_(2)+O_(2) At equlibrium 0.6 moles of SO_(2) were formed. The equlibrium constant for the reaction will be

Answer»

`0.36`
`0.45`
`0.54`
`0.675`

Solution :`underset((1-0.6))(2SO_(3))hArrunderset((0.6))(2SO_(2))+underset((0.3))(O_(2))`
`K_(C)=([SO_(2)]^(2)[O_(2)])/([SO_(3)])=(0.6xx0.6xx0.3)/(0.4xx0.4)=0.675.`


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