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One mole of water at 100^@C is converted into steam at 100^@C at a constant pressure of 1 atm. The change in entropy is ____________. (heat of vaporization of water at 100^@C=540cal/g) |
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Answer» 8.74 Here, heat of vaporisation = 540 cal/gm `=540xx18 cal mol^(-1)` Temperature of WATER = 100 + 273 = 373 K `THEREFORE` entropy change = `(540xx18)/(373) = 26.06 cal mol^(-1) K^(-1)`. |
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