One moles of anhydrous `AB` dissolves in water and liberates `21.0 J mol^(-1)` of heat. The valueof `DeltaH^(Theta)` (hydration) of `AB` is `-29.4 J mol^(-1)`. The heat of dissolution of hydrated salt `AB.2H_(2)O(s)` isA. `50.4 J mol^(-1)`B. `8.4 J mol^(-1)`C. `-50.4 J mol^(-1)`D. `-8.4 J mol^(-1)`

One moles of anhydrous `AB` dissolves in water and liberates `21.0 J m

1.	One moles of anhydrous `AB` dissolves in water and liberates `21.0 J mol^(-1)` of heat. The valueof `DeltaH^(Theta)` (hydration) of `AB` is `-29.4 J mol^(-1)`. The heat of dissolution of hydrated salt `AB.2H_(2)O(s)` isA. `50.4 J mol^(-1)`B. `8.4 J mol^(-1)`C. `-50.4 J mol^(-1)`D. `-8.4 J mol^(-1)`
Answer» Correct Answer - B `DeltaH_(sol)` (anhyd. Salt) `=[DeltaH_(sol)("hydrated salt") + DeltaH_("hydration")]`

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One moles of anhydrous `AB` dissolves in water and liberates `21.0 J mol^(-1)` of heat. The valueof `DeltaH^(Theta)` (hydration) of `AB` is `-29.4 J mol^(-1)`. The heat of dissolution of hydrated salt `AB.2H_(2)O(s)` isA. `50.4 J mol^(-1)`B. `8.4 J mol^(-1)`C. `-50.4 J mol^(-1)`D. `-8.4 J mol^(-1)`

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