InterviewSolution
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InterviewSolution
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One number is chosen from numbers 1 to 100. Find theprobability that it is divisible by 4 or 6? |
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Answer» Correct Answer - `33/100` Here, `S = {1, 2, 3, 4, …, 99, 100} rArr n(S) = 100.` Let `E_(1) =` event of getting a number divisible by 4. And, `E_(2) =` event of getting a number divisible by 6. Then, `E_(1) nn E_(2) = ` event of getting a number divisible by both 4 and 6, i.e., divisible by 12 (LCM of 4 and 6). `therefore E_(1) = {4, 8, 12, ..., 100} rArr n(E_(1)) = 25`. `E_(2) = {6, 12, 18,.., 96} rArr n(E_(2)) = 16.` `(E_(1) nn E_(2)) = {12, 24, 36,.., 96} rArr n(E_(1) nn E_(2)) = 8.` Now, use `P(E_(1) uu E_(2)) = P(E_(1)) + P(E_(2)) - P(E_(1) nn E_(2)).` |
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