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One of the most efficient engines ever developed operated between 2100K and 700K. Its actual efficiency is 40%. What percentage of its maximum possible efficiency is this? |
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Answer» `T_1=2100K`, `T_2=700K`, `eta_(actual)=40%` Maximum possible effiency of Carnot engine is `eta_(max)=1-(T_2)/(T_1)=1-700/2100` `=0.666=66.6%` Actual efficiency as the percentage of the maximum possible efficiency is `(eta_(actual))/(eta_(max))xx100=40/66.6xx100` `=60%` |
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