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One of the two digits of a two digit number is 4 times the other number. If you interchange the digits of this two digit number and add the resulting number to the original number,you get 110. What is the original number? I need answer fast!!! Please send me fast |
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Answer» Let the digit in the UNIT place be x. Then, tens place be 4x so, the TWO digit number is 10×4x+x with interchanging of the digits, the number will be 10 × x + 4xAccording to the question, 10X + 4x + 4ox + x = 110or, 55x = 110or, x = 110/55or, x = 2 Hence, the original number = 40x + x = 40×2+2 = 80 + 2 = 82. |
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