1.

One quarter sector is cut from a uniform circular disc ofradius R. This sector has mass M. It is made to rotate about a line perpendicular to its plane and passing through the centre of the original disc. Its moment of inertia about the axis of rotation is

Answer»

`1/2MR^(2)`
`1/4MR^(2)`
`1/8MR^(2)`
`sqrt2MR^(2)`

SOLUTION :This sector is cut from the disc of mass 4M and radius R.
Moment of INERTIA of that disc = `1/2(4M)R^(2)`
Moment of inertia of sector=`1/2(4M)R^(2)xx1/4=1/2MR^(2)`


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