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One second after being thrown straight down, an object is falling with a speed of 20 m//s. How fast will it be falling 2 seconds later ?

Answer»

SOLUTION :Call down the positive direction, so `a = +g and v_(0) = +20 m//s` . We're given `v_(0),a, and t`, and asked for v. Since s is MISSING, we use Big Five #4.
`v= v_(0)+at =(+20 m//s)+(+10 m//s^(2))(2 s)=40 m//s`


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