One straight wire carries 5 A. Angles made by line segments joining point P at 10 cm on perpendicular bisector and the two ends of wire, with the wire are 60^(@) each. Then magnetic field at this point will be ______ T.

One straight wire carries 5 A. Angles made by line segments joining po

1.	One straight wire carries 5 A. Angles made by line segments joining point P at 10 cm on perpendicular bisector and the two ends of wire, with the wire are 60^(@) each. Then magnetic field at this point will be ______ T.
Answer» `3mu_(0)` `3.98mu_(0)` `39.8mu_(0)` zero Solution :`B=(mu_(0)I)/(4piy)(cosalpha_(1)+cosalpha_(2))` = `(mu_(0)xx5)/(4pixx0.1)[cos60^(@)+cos60^(@)]` = `(50mu_(0))/(4xx3.14)[2COS60^(@)]=3.98089xx2xx1/2mu_(0)` `thereforeB~~3.98mu_(0)T`

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One straight wire carries 5 A. Angles made by line segments joining point P at 10 cm on perpendicular bisector and the two ends of wire, with the wire are 60^(@) each. Then magnetic field at this point will be ______ T.

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