1.

)one67. A 200 g sample of hard water is passed through the column of cation exchange resin, in which Ht is exchanged by Ca"*The outlet water of column required 50 mL of 0.1 M NaOH for complete neutralization. What is the hardness of Ca2 ion inppm(1) 250 ppm(2) 500 ppm(3) 750 ppm(4) 1000 ppm

Answer»

N1 x v1 = n2 x v2

Thus, 0.1 x 50 = n2 x 200

Thus n2 (normality) of hard water is 0.025

Normality x equivalent wt = gms/lt. I. e. 0.025 x 20 (equipment wt of CA) =0.5 g/L or 500 ppm as Ca or 500 x 50/20 = 1250 ppm as CaCO3



Discussion

No Comment Found

Related InterviewSolutions