\operatorname { cos } 38 ^ { \circ } \operatorname { cos } 52 ^ { \cir – InterviewSolution

InterviewSolution

1.	\operatorname { cos } 38 ^ { \circ } \operatorname { cos } 52 ^ { \circ } - \operatorname { sin } 38 ^ { \circ } \operatorname { sin } 52 ^ { \circ } = 0
Answer» <p>Cos 38 = Cos (90-52)Cos 38 = sin 52Sin 38 = sin ( 90 - 52)= Cos 52Cos 38cos52-sin38sin52sin52cos52 - cos52sin52 = 0</p>

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