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Optically active 2-iodobutane on treatment with Nal in acetone gives a product which does not show optical activity. Explain briefly. |
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Answer» Solution :There occurs breaking and reforming of C-1 bond. This resutls into two enantiomers which FORM racemic mixture which does not show optical activity due to EXTERNAL compensation. `H-UNDERSET(C_(2)H_(5))underset(|)overset(CH_(3))overset(|)(C)-Ioverset((i)-I^(-))underset((ii)+I^(-))rarrH-underset(C_(2)H_(5))underset(|)overset(CH_(3))overset(|)(C)-I+I-underset(C_(2)H_(5))underset(|)overset(CH_(3))overset(|)(C)-H` |
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