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| 1. |
Optically active 2-iodobutane on treatment with sodium iodide in acetone gives a product which does not show optical activity. Explain |
| Answer» SOLUTION :OPTICALLY ACTIVE 2-iodobutane dissociated to FORM iodide ion and the carbocation. The iodide ion then attacks the flat carbocation from either side resulting in a mixture of two enantiomeric products in equal amounts, which constitutes a racemic mixture which does not show optical activity. | |